Question

Simplify: (i) (a^3 b^2 c^4)/(ab^3 c^(-3) )

Answer 1

You would like to simplify I bet :)
Now you need to recall the law of exponents!
\[\frac{x^a}{x^b}=x^{a-b}\] ;
\[ x^{a} x^{b}=x^{a+b} \]

Answer 2

\[\frac{a^3 b^2 c^4}{ab^3c^{-3}}=\frac{a^3}{a} \cdot \frac{b^2}{b^3} \cdot \frac{c^4}{c^{-3}}\]

Answer 3

So using just the first thing I wrote rewrite this

Answer 4

How about I rewrite just a little so you can try to rewrite my writing of it
\[\frac{a^3}{a^1} \cdot \frac{b^2}{b^3} \cdot \frac{c^4}{c^{-3}}\]
So for that first little part
\[\frac{a^3}{a^1}=a^{3-1}=a^2\]
What do you think if we apply that first rule here:
\[\frac{b^2}{b^3}\]