Question

Help. When factoring completely, how do I do it?
63a^2+294ap+343p^2

Answer 1

63a^2+294ap+343p^2



7(9a^2+42ap+49p^2)



7(9a^2+21ap+21ap+49p^2)



7((9a^2+21ap)+(21ap+49p^2))



7(3a(3a+7p)+(21ap+49p^2))



7(3a(3a+7p)+7p(3a+7p))



7(3a+7p)(3a+7p)



7(3a+7p)^2


So 63a^2+294ap+343p^2 completely factors to 7(3a+7p)^2



In other words,

63a^2+294ap+343p^2=7(3a+7p)^2

for all values of 'a' and 'p'

Answer 2

Thank you for showing the work and working it out for me, makes it much more understandable.

Answer 3

you're welcome