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Mathematics 8 Online
OpenStudy (anonymous):

One end of a rope is fastened to a boat and the other end is wound around a windlass located on a dock at a point 4 meters above the level of the boat. (see picture in the book) If the boat is drifting away from the dock at the rate of 2 meters/min , how fast is the rope unwinding at the instant when the length of the rope is 5 meters . (Let denote the length of rope at time .)

OpenStudy (anonymous):

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OpenStudy (anonymous):

you want \[y'\] and you know that \[y^2=4^2+x^2\] and therefore \[2yy'=2xx'\] you are given that \[x'=2\]so you can plug in the numbers to get the answers

OpenStudy (anonymous):

unless my picture is bad

OpenStudy (anonymous):

no i think your pic is right

OpenStudy (anonymous):

or atleast i drew the same thing

OpenStudy (anonymous):

so now that i know x^prime what do i do?

OpenStudy (anonymous):

then this should be easy enough. you have \[yy'=xx'\] \[x'=2,x=5\] and by pythagoras we find \[y=\sqrt{4^2+5^2}=\sqrt{41}\]

OpenStudy (anonymous):

was x prime in the problem?

OpenStudy (anonymous):

when it says it is pulling away at 2ft/sec

OpenStudy (anonymous):

so you get \[\sqrt{41}y'=10\]

OpenStudy (anonymous):

if you label the distance from the boat to the dock as x, then you know x' = 2 because that is what you are told

OpenStudy (anonymous):

ok i see

OpenStudy (anonymous):

the boat is drifting away from the dock at the rate of 2 meters/min

OpenStudy (anonymous):

that tells you x' = 2, if you label that distance as x

OpenStudy (anonymous):

you need to call it something because you are trying to find the rate of change of the rope, and you only know the rate of change of the boat. your goal is to find an equation that relates them so you can differntiate and solve for the rate of change that you want, using the rate of change that you know

OpenStudy (anonymous):

so the sqrt(41)y^prime = 10 and i just solve for y^prime and thats my answer

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