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Mathematics 18 Online
OpenStudy (anonymous):

How do I find the general solution to this ODE. http://i.imgur.com/Qbv7N.jpg

OpenStudy (anonymous):

I tried getting x's on LHS and t's on the RHS. but it's not working out for me.

myininaya (myininaya):

So yep we can do separation of variables here :)

myininaya (myininaya):

\[\frac{dx}{dt}=1+x+t^2+t^2x\] Is what we have right?

myininaya (myininaya):

\[\frac{dx}{dt}=(1+x)+(t^2+t^2x)\]

myininaya (myininaya):

\[\frac{dx}{dt}=1 \cdot (1+x)+t^2 \cdot ( 1+x)\]

myininaya (myininaya):

\[\frac{dx}{dt}=(1+x)(1+t^2)\] Do you see where to go with this?

myininaya (myininaya):

Multiply the dt on both sides Divide both sides by the (1+x)

OpenStudy (anonymous):

Multiply by dt and divide by 1+x?

myininaya (myininaya):

lol yes :)

OpenStudy (anonymous):

Ahh, I see. I never thought of factorizing!! Thank you

myininaya (myininaya):

\[\frac{dx}{1+x}=(1+t^2) dt \]

myininaya (myininaya):

:) factoring is sometimes needed :)

OpenStudy (anonymous):

Do I just integrate then?

myininaya (myininaya):

Yep for sure

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