A fireman has to reach a burning building. Determine the length of the shortest ladder that will reach over a 2 metre high fence to the burning building which is 1 metre behind the fence. Need the 2 Equations to sub so I can then take derivative and set to 0! someone please find my 2 equations I have the length of ladder one but need the limiting equation!!!
z² = x² + y²
yes, and now the limiting equation? that I will use to substitute into c^2 = a^2 + b^2 to obtain a single variable on the right side and then do the derivative
the length of ladder is limited!
=> xdx/dt + ydy/dt = 0
do I need to carry the exponent on Z over before deriving?
It's constant, so "No"
ok so I have \[L^2 = (y+1)^2 + (x+2)^2\]
Do you post the whole problem at all?
yea thats the whole thing
see what I mean I need a second equation to limit that one to one variable before I can derive
Is it Related Rate problem? because without the data of dx/dt and dy/dt, it doesn't look right!
no its a optimization problem from grade 12 calculus... part of a take home assignment
Let me check, but keep Z to take derivative first!
Do you how to apply similar triangles?
xy = 2 => y = 2/x That's limitation!
OK i had that before, so I am subbing that into the original hypotenuse equation the deriving and setting to zero?
then*
After taking derivative, subs y = 2/x, solve for x, y, z
so take the derivative of L2=(y+1)2+(x+2)2 then sub?
sorry the 2s are exponents
?
wait I'm not following, I gotta start from the beginning
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