Question

Find the derivative of the function:
y = ∫ (from 2x to 3x+1) sin(t^4)dt

Answer 1

\[d/dt \int_{2x}^{3x+1} Sin(t^4) dt\]

is that it?

Answer 2

yes!

Answer 3

how do I solve it?

Answer 4

well, we won't be able to integrate it

but just assume that we did so we just some function F(t)

now we substitute limit into F(t)

F(3x+1)-F(2x)

now take derivative d/dx

well you took a function , integrate it , and well you differentiate it back ; you should get same thing back .

3 Sin(3x+1) - 2 Sin(2x)

Answer 5

why can't we integrate it?