Solve the equation: (3x - 2)(7x + 1) = 0.
(3x - 2)(7x + 1) = 0 Put (3x - 2) =0 or (7x + 1) = 0 x = 2/3 x=-1/7 actually do you understand how to deal with such kind of questions?
I don;t :(
Give you an easy one to try x (5) = 0, what is x?
0
How can you get the answer?
Multiplying something by zero always results in a zero.
Yup.. that's the same when you consider the xy=0 What would you think if xy=0? what is the possible value for x or y?
Hint: remember what you've said just now 'Multiplying something by zero always results in a zero.'
I'm not exactly sure how to work the double letters unfortunately. I know if you multiple one by zero it gets zero? I think.
Yup.. you're quite close to the point.. For the product of 2 unknowns, the either one should be =0 to give 0 as the result (of course both of them can be 0), Do you understand so far?
Yeah, I understand so far. Until numbers get added into the situation which makes it twice as difficult.
When you see something like (3x - 2)(7x + 1) = 0. Just consider (3x - 2) =y and (7x + 1)=z So yz=0 Understand so far?
Sort of.
So, either y = 0 or z=0 can make the product =0, understand?
Now it makes more sense.
So remember you let y=(3x - 2) and z=(7x + 1) Put it back to y = 0 or z=0 respectively, and solve for it separately, understand?
That part kind of confuses me the final solve.
Hmmm... which part you don't understand?
So remember you let y=(3x - 2) and z=(7x + 1) Put it back to y = 0 or z=0 respectively, and solve for it separately, understand?
So remember you let y=(3x - 2) and z=(7x + 1) <- understand?
Yes I understand that part.
either y = 0 or z=0 can make the product =0, understand <- understand?
That's where I get confused.
yz=0 either y = 0 or z=0 can make the product =0, understand?
Yeah
so y= 3x-2 =0 or z=7x+1=0, understand?
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So 3x-2 =0 or 7x+1=0 and solve the 2 equations, understand?
I don't know how to solve them both together.
3x-2 =0 x = 2/3 or 7x+1 =0 x=-1/7 Just solve it separately
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