Question

can someone solve this?

Answer 1

y = 4x^2 − 7x + 2

Answer 2

go callisto! :DDD

Answer 3

what?

Answer 4

Try the Quadratic Formula. I don't think this one will factor over the set of rationals.

Answer 5

all values lying on the line of the curve y = 4x^2 − 7x + 2

Answer 6

I think y=0 if you need to solve it?

Answer 7

What are the instructions for this problem?

Answer 8

^that's what go callisto meant @katlin95

Answer 9

i just need to solve it, it was posted up in the discussion area for my schooling

Answer 10

i knw igbasallote

Answer 11

Well, i assume if you need to solve it, put y=0
0 = 4x^2 − 7x + 2
Use the quadratic formula:
\[x = (-b \pm \sqrt{b^2-4ac})/(2a)\]
Put a=4 , b=-7, and c=2 into the formula and solve for x :)

Answer 12

wow!

Answer 13

can you solve it?

Answer 14

x = (7 +/- Square root of 17)/ 8

Answer 15

\[\text{Solve this by completing the square}\]

Answer 16

\[\begin{array}{l} \text{$$$ $}\text{divide both sides by }4: \\ x^2-\frac{7 x}{4}+\frac{1}{2}=0 \\ \text{Subtract }\frac{1}{2}\text{ from both sides:} \\ x^2-\frac{7 x}{4}=-\frac{1}{2} \\ \text{Add }\frac{49}{64}\text{ to both sides:} \\ x^2-\frac{7 x}{4}+\frac{49}{64}=\frac{17}{64} \\ \text{factor the left hand side:} \\ \left(x-\frac{7}{8}\right)^2=\frac{17}{64} \\ \text{take the square root of both sides} \\ \left|x-\frac{7}{8}\right|=\frac{\sqrt{17}}{8} \\ \text{eliminate the absolute value} \\ x-\frac{7}{8}=-\frac{\sqrt{17}}{8}\text{ and }x-\frac{7}{8}=\frac{\sqrt{17}}{8} \\ \text{add }\frac{7}{8}\text{ to both sides} \\ x=\frac{1}{8} \left(7-\sqrt{17}\right)\text{ adn }x=\frac{1}{8} \left(7+\sqrt{17}\right) \\\end{array}\]

Answer 17

wow.. thankyou so much!!!!! yer da bomb man!