Question

Anyone help me with this problem?
Each hour, the hour hand of a clock moves This is 1/12 'th of the way around the circle. This is 1/12· 360° = 30°. Each minute, the hour hand moves This is 1/60'th of the distance it moves in one hour. This is 1/60· 30° = 0.5° Each minute, the minute hand moves 1/60'th of the way around the circle. This is 1/60· 360° = 6°. The angle is...?

Answer 1

you didn't post a question yet

Answer 2

the angle made by the difference between where the hand was and now is one unit of time later.

Answer 3

@eseidl, I did. it's in the question

Answer 4

How do I solve?

Answer 5

Do I just multiply then add the numbers all up?

Answer 6

What are you trying to solve for?

Answer 7

Use the following information to find the angle between the hands of a clock at 5:15.

Answer 8

so the degree =?

Answer 9

Find the angle of the hour hand first:
5 is 5/12*360 around the clock,
5.15 is 1/4 *1/12 more around the clock.
5/12*360 = 150
1/4*1/12*360 = 7.5
So, the hour hand is 157.5 from 12, and the minute hand at 90 from 12.
157.5-90 = 67.5 (difference between the hour and minute hand)
157.5 (difference between hour and second (assuming the seconds are at 00))
90 (difference between minute and second)

Does that help?

Answer 10

how do I solve?

Answer 11

Um, so do I just add those all together?

Answer 12

so is the answer 90 degrees?

Answer 13

Your question:
Use the following information to find the angle between the hands of a clock at 5:15.
There are 3 different hands on the clock, could be seen as 3 points; A, B, C. You want to measure the degree at the origin, where they connect O. So there are 3 angles to find.

AOB
AOC
BOC

Where A is the Hour hand, B is the Minute hand and C is the Second hand and the time is 5.15.00:

AOB = 157.5-90 = 67.5
AOC = 157.5
BOC = 90