Question

1.48

Answer 1

what does that x = 1.48 represent here? you don't have an equation...

Answer 2

can you show how you "got" x=1.48 here?
what method did you use?
btw @Luis Rivera I think that is incorrect

Answer 3

you just put it into your graphing calculator?

Answer 4

that is the zero

Answer 5

\[3^{2x+1}-70=0\]
\[3^{2x+1}=70\]
\[2x+1=\frac{\ln(70)}{\ln(3)}\]
\[2x=\frac{\ln(70)}{\ln(3)}+1\]
\[x=\frac{1}{2}(\frac{\ln(70)}{\ln(3)}+1)\]

Answer 6

of the function\[y=3^{2x+1}-70\]why you are not allowed to use logs as to solve this is beyond my comprehension though...

Answer 7

still inconceivable, using the graphing calculator left you unable to recognize what "finding the zero" actually means
finding the zero's means we want to know the value of x when y=0, hence\[y=0=3^{2x+1}-70\]which you should definitely know in 11th grade math

Answer 8

if you're only allowed to use your graphing calculator, make sure you put the function in correctly... y= 3^(2x+1) - 70... the zero I got from my calculator is x = 1.43

Answer 9

yes, satellite is always right
...but it would be nice if you walked away from this knowing what it means to "find the zero's" of a function

Answer 10

he gave the exact answer.

Answer 11

which, if you are not allowed to use logs, is inadmissible

Answer 12

put what satellite has into your calculator and you will se that 1.48 is an approximation of the exact answer

Answer 13

i.e. they are the same answer, but satellites is exact

Answer 14

...your is an approximation