Question

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Answer 1

this is one of those discrete recurrence relations that can be modeled by Pert i think

Answer 2

1= 10 (1/2)^(t/24)
Solve for t
0.1 = (1/2)^(t/24)
ln (0.1) = (t/24,360) ln(0.5)
t/24,360 = ln(0.1) / ln(0.5)
t = 24,360 ln(0.1) / ln(0.5)
t= 80922.1683
80,922 years

Answer 3

ln(2)/24,360 = r

1 = 10e^(ln(2)/24360 * t)

.1 = e^(ln(2)/24360 * t)

ln(.1) = ln(2)/24360 * t

ln(.1)/ln(2) = t/24360

24360ln(.1)/ln(2) = t

would be my guess if i did my mathing right

Answer 4

there are a few ways to go about it, so that migh tbe a plausible method

Answer 5

there are other sites?

Answer 6

the answer i found looks to model the e^x graph so it says t is negtaive; but the negative part can simply be ignored

Answer 7

well, it should be about 80922 im not quite sure how your using the calculator tho :)

Answer 8

http://www.google.com/#hl=en&sugexp=llsin&gs_nf=1&pq=24360ln(.1)%2Fln(2)&cp=19&gs_id=1p&xhr=t&q=10(1/2)%5E(t/24360)-1&pf=p&sclient=psy-ab&oq=10(1/2)%5E(t/24360)-1&aq=&aqi=&aql=&gs_l=&pbx=1&bav=on.2,or.r_gc.r_pw.r_qf.,cf.osb&fp=81eee28ba52115e6&biw=1280&bih=930

google gives a graph now, thats pretty cool

Answer 9

....

Answer 10

its even got a tracker on it lol

Answer 11

you should but it might get squiched on the screen, i aint got me ti83 with me to test out tho

Answer 12

yw

Answer 13

@kk alright fine...i guess

Answer 14

yourwelcome..

Answer 15

i see you edited to a "."

Answer 16

@rihanna, come

Answer 17

Mhmm?