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OpenStudy (anonymous):
At 25 °C and 785 Torr, carbon dioxide has a solubility of 0.0351 M in water. What is its solubility at 25 °C and 1210 Torr?
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OpenStudy (anonymous):
mathway.com google http://www.wolframalpha.com/ sorry i wish i could help... :)
OpenStudy (kainui):
Try asking in Chemistry, someone should know there. Unfortunately it doesn't look like you can use PV=nRT here.
jhonyy9 (jhonyy9):
- so than i think you can using here the rule of 3 simple : 785 Torr ----- 0,0351 M solubility 1210 Torr ----- x -------------------- x=1210 *0,0351 /785 = - hope you can make the calcules good luck bye
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