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how do you find the inverse of f(x): f(x)=2/3x+6
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It's a 4 step process
First, replace f(x) with "y"
\[f(x)=\frac{2}{3}x+6\] or \[f(x)=\frac{2}{3x+6}\]
So you've got f(x) = 2/3x+6 y = 2/3x + 6 Next, the "x" and "y" switch places.
So you've got: x = 2/3y +6 Next, you solve for "y"
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x=2/3y+6 Subtract 6 from both sides x-6 = 2/3y Then, you can multiply by 3/2 on both sides, and you'll have that y by itself. 3/2(x-6) = y
And the last step is to replace y with: \[ f^{-1}(x)\]
So you're left with: \[f^{-1}(x)=\frac{3(x-6)}{2}\]
Or, if you'd prefer: \[ f^{-1}(x)=\frac{3}{2}x - 9\]
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