Question

Can someone please help me...please?




How many ways can 6 students be arranged in a lunch line?



A family has a bike rack that fits 7 bikes but they only have 5 bikes. How many ways can the bikes fit in the bike rack?




How many 4-digit pin numbers are available if no number is repeated?

Answer 1

helllpp mee please!!!!!!

Answer 2

lunch line: 6! = 720

Answer 3

thhaaaannnnkkk yoooouuuuu ,and also the other problems... and could you possibly explain to me plz? (i'll give u a meeedddaaalll?????????) >:D

Answer 4

it's the formula such that having x to arranged, then we have x factorial (x!)
so if it's 10 students then 10!. 20 will be 20!, and so on

Answer 5

pin number
we have 10 digits number 0-9
so we can choose the first number from 10 numbers
then we choose the 2nd number from 9 numbers (since no number repeated)
then we choose the 3rd number from 8 numbers
then we choose the last number from 7 numbers left
finally we have: 10*9*8*7 = 5040

Answer 6

we the numbers is allowed to be repeated, then we have 10 ways to choose each number, and so:
10*10*10*10 = 10^4 = 10000

Answer 7

wait... r u talking about the bike one?

Answer 8

no the pin number

Answer 9

oh... so then the real answer's suppose to be 10000... rite?

Answer 10

no the answer for your pin number is 5040
the 10000 is the insight idea

Answer 11

oh i get it now.. so If the numbers can be repeated, dat means dat dere are 10,000 possiblities, correct?

Answer 12

yes

Answer 13

so then wut about the biking one?

Answer 14

do you know about permutation?

Answer 15

ya

Answer 16

is it 7*6*5*4*3=2520?

Answer 17

yes, the same result if you apply 7P5 = 7!/(7-5)!

Answer 18

oh, okay then and thank you
but i also haf 2 more questions if u don't mind:
How many ways can you select 3 sheriff deputies from 8 candidates?
How many handshakes can occur between 5 people if everyone shakes hands?
And can u also explain each one? i would be grateful and thank you! :D

Answer 19

deputies candidate: having 3 choosing from 8
so it's 8C3 = 8!/[3!*(8-3)! = 112

Answer 20

i'm sorry, i can't understand all dat... stuff

Answer 21

you need to choose 3 people from 8 candidates
and 8C3 is the formula, the same formula with permutation

Answer 22

how did u get 112?

Answer 23

8C3 = 8!/[3!*(8-3)! = 8!/[3!*5!
= (8*7*6*5*4*3*2*1) / [(3*2*1)*(5*4*3*2*1)]
= 8*7*6 / 3*2 = 8*7 = 56, this is the correct answer

Answer 24

oh thank you and good night and then i'll be off.. with my personal stuff....... i'll sorta "contact" you if I'll need anymore help...
;)

Answer 25

ok, good night

Answer 26

waaaaaiiiiitttttt...... you forgot to explain the problem about the handshakes!!!!!

Answer 27

is it 3125? because then it's like 5*5*5*5*5...right?

Answer 28

we need to have 2 people to shake hand. So we need to choose 2 people from 5 people to have the hand shake.
so 5C2 = 5!/[2!*(5-2)!] = 5!/(2!*3!)
= 5*4*3*2*1 / [(2*1)*(3*2*1)]
= 5*4 / 2 = 10

Answer 29

oh never mind i get it then thanks... so its:
(5*4)/(2*1)=10
rite?

Answer 30

no answer?
fne
good night then