Question

Radius of curvature=35m, linear speed=10km/hr, find the angular velocity and acceleration. Please help me.

Answer 1

Use
\[v=wR\]
Put v=10*5/18 m/s
R=35

Answer 2

Can I use linear Speed=10km/hr=2.778m/s directly substitute in the formula a=v^2/R
a=2.778^2/35=0.2208m/s^2. Is this correct?

Answer 3

Yes it is!

Answer 4

\[\alpha=a/R \]
alpha is the angular acceleration

Answer 5

@Natan
In this example angular acceleration is zero.
and (linear) acceleration is purely centripetal.

If acceleration had a component tangent to the circle, then we would have:
\(\large\alpha=\huge\frac{a_t}{R}\)

Answer 6

oh sorry !!
is true
it is a uniform circular motion

thanks!