Solve the following equations, giving your ans correct to 3 sig. fig. thx u.

a) 2e^(2x+1) = e^(x+1) +15e
b) 2e^2x = 5e^(x+1) - 2e^2

Question

Solve the following equations, giving your ans correct to 3 sig. fig. thx u.

a) 2e^(2x+1) = e^(x+1) +15e
b) 2e^2x = 5e^(x+1) - 2e^2

amistre64 · Answer

so how would you go about solving this?

amistre64 · Answer

this property of exponents might come in handy:$$\large b^{n+m}=b^n*b^m$$

zarkon · Answer

u=e^x for the 2nd

anonymous · Answer

first one, divide both sides by "e" to get 
$$2e^{2x}=e^x+15$$ then perhaps 
$$2e^{2x}-e^x-15=0$$ a nice quadratic equation, that you can solve by factoring

anonymous · Answer

second one 
$$2e^{2x} = 5e^{x+1} - 2e^2$$
$$2e^{2x}=5e(e^x)-2e^2$$
$$2e^{2x}-5e(e^x)+2e^2=0$$ quadratic formula for this one