Question

lim(h→0) ((1+h)^2+1-(1^2+1))/h)

Answer 1

this is the derivative of
\[x^2\] at x = 1
so you should get 2

Answer 2

quite not .. though answer would be 2

Answer 3

\[(1+h)^2+1=1^2+2h+h^2+1=2+2h+h^2\]
\[1^2+1=2\]
\[2+2h+h^2-2=2h+h^2\]
\[\frac{2h+h^2}{h}=\frac{h(2+h)}{h}=2+h\]

Answer 4

i guess x^2+1

Answer 5

yes you are right it would be the derivative of
\[x^2+1\] at x = 1

Answer 6

thanx

Answer 7

yw