If 62.7 g N2 react with 23.8 g H2 according to the reaction below, how many grams of ammonia (NH3) can be produced, and how many grams of the excess reactant will be left over? Unbalanced equation: N2 + H2 → NH3
Is this correct? Balanced- N2 + 3H2 = 2NH3 28g N2 gives 34g ammonia So 62.7g N2 gives 34/28 x 67.2g NH3 From equation, 28g N2 react with 6gH2 so 62.7g N2 react with 6/28 x 62.7 g H2 take this amount away from 23.8g to find the excess H2
No.. This is not a practice exam. This is a module quiz from FLVS and it's cheating if you use this answer. Plus it has a obvious mistake in it. Mr. Carlyle FLVS Chemistry Instructor This question is a violation of the OpenStudy Guidelines. The question is from an online school plus a violation by solicitation for members to unknowingly assist them cheating on an exam. 30653065chem30653065
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