How do you find the zeros of f(x)= x^3+11x^2-150x-1512; -4

Question

anonymous · Answer

they are telling you that x+4 is a factor? so you can divide by x+4 using long division or -4 using synthetic division and solve the quadratic quotient

anonymous · Answer

okay thanks

anonymous · Answer

with synthetic divison I got -2562 as the answer???

anonymous · Answer

you should get a quotient in the form of ax^2+bx+c, not a single constant

anonymous · Answer

what is that -4 after f(x)?  -4 is not a zero to f(x) so why is it listed in the problem?

anonymous · Answer

The directions say "Given one zero of the polynomial function, find the other zeros"

anonymous · Answer

yes, but -4 is not a zero of f(x) in your problem...did you type it correctly in here?

anonymous · Answer

yes, thats how it was given in the book, thats what I was unsure of...

anonymous · Answer

maybe its a typo.  you can graph it on your calculator and find the zeros if you want, or you can use descartes rule of signs and the rational zeros theorem, but there are a huge number of factors of 1512 for trial and error

anonymous · Answer

I don't know whats up with that because there are ten problems in the book like those I typed...but thanks i'll try try putting it in my calculator.

anonymous · Answer

one zero is -14, i'll give you that.

asnaseer · Answer

Dockworker is right - this is definitely a typo, -14 is one root of this polynomial

anonymous · Answer

okay