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Suppose y is inversely proportional to x and the constant of proportionality equals 4. What is the minimum of the sum of x and y if x and y are both positive?
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y = 4/x huh? minimum...does this have something to do with calculus?
yes this is a calculus problem
y=4x^(-1) y'=-4/x^2
ohh wait lol wrong approach
minimize x+y
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x+y=x+4x^(-1) minimize f(x)=x+4x^(-1)
f'(x)= 1 -4x^(-2)
so take derivative and set it to zero?
1-4x^(-2)=0 x^2-4=0 x=+/-2 but since x is positive, we take x=2
that means y=4/x=4/2=2
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the answer's 2? i tried 2 earlier but my hw site said it was wrong.
minimum is 4.. 2+2 is 4
o
wait how did you go from that 1-4x^(-2)=0 to that x^2-4=0
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