How much heat is required to raise the temperature of 210g OF CH3OH(l) from 22.0 to 30.0deg C and then vaporize it at 30.0C? Use molar heat capacity of CH3OH(l) of 81.1 J: mol^-1 K^-1.

Question

How much heat is required to raise the temperature of 210g OF CH3OH(l) from 22.0 to 30.0deg C and then vaporize it at 30.0C? Use  molar heat capacity of  CH3OH(l) of 81.1 J: mol^-1 K^-1.

anonymous · Answer

we use our handy dandy q = (mas)(Csp)(deltaT) where Csp is molar heat capacity and delta T change in temp(final - initial) we just plug and chug. $$q= (CH _{3}OHmoles)(81.1J/molK)(30.0K-22.0K) $$ The only hard part is converting the ch3oh into moles. :)

I don't know what you mean vaporize it at 30.0C That doesn't make sense. Are you asking if it is a vapor at that temp?