Question

Given each scalar equation, write a vector equation. x=8

Answer 1

I was thinking that the normal vector was [8,0] and that the direction vector was [0,-8] and the position vector was [8,0].

Answer 2

I was wrong.

Answer 3

My final answer was [x,y]=[8,0]+t[0,-8]. But I am wrong.

Answer 4

MYsesshou, are you my savior in this dark time?

Answer 5

Assassin, are you able to assist me?

Answer 6

Actually, I'm not quite sure. Sorry !!
Sorry for lag. I have been fighting my computer and this site for like an hour.

Answer 7

I think everyone has. Ok. Oh well.

Answer 8

was that the only info you're given?

Answer 9

Yes.
Alongside the info in the textbook explaining how to do this.

Answer 10

I'm still searching, but can you apply something like this? http://www.blurtit.com/q1900770.html (google'd)

I don't have your book... is it a calc book?

Answer 11

I dunno.
Yes, it is a Calculus and Vectors book.

Answer 12

Are you able to help?

Answer 13

Probably not, but I've been searching

Answer 14

I'll rally up others just in case.

Answer 15

Sorry, it's just been too long for me for this to be recalled.

Answer 16

Yeah. Happened to me when I was helping someone else on inequalities.

Answer 17

@Zarkon Uh, someone told me to ask you.

Answer 18

why is your answer wrong?

Answer 19

The actual answer is [x,y]=[8,2]+t[0,1].

Answer 20

Any clue?

Answer 21

I've double-checked to make sure the facts are right.

Answer 22

the -8 isn't necessary but acceptable.... both your eq. and answer equation are acceptable...

Answer 23

direction vector can be any vertical vector... starting point postion vector can refer to any point on line
Infinite acceptable answers.

Answer 24

Like, I know that [8,0] can be anything, but my answer still isn't right in terms of t[0,1].

Answer 25

Sorry IsTim, I've searched through my calc book and solutions manual, but I guess 8-9 years is too long to remember enough of this. Hope PaxPolaris is able to help you understand. :)

Answer 26

direction vector can be any vertical vector ... [0,1] and [0,-8] are both parallel to the line so both are acceptable ... any vector [0,C] is acceptable.

Answer 27

Wait, you're sure you're not talking about position vector?

Answer 28

no, we're done with that...??

Answer 29

I don't know, they way you describe the direction vector sounds like the way my teacher described a position vector.

Answer 30

Position Vector: of any 1 point on the line

Direction Vector: any vector parallel to the line

Answer 31

But then what's the constant?

Answer 32

the slope of the direction vector is constant ... the length of the direction vector is irrelevant

Answer 33

Ok. I'll just leave this question as is for now. Thanks for the help anyways, PAx.

Answer 34

eg. if your direction vector is [1,2]:
it can also be [2,4] , [3,6], [-5,-10]....[n,2n]

preferably you'd use the simplest form i.e. [1,2] or in your case [0,1] instead of [0,-8]
http://www.netcomuk.co.uk/~jenolive/vect3.html

Answer 35

Hey Sess, I'm good now. Thanks for staying though.
I'll take a look at it Pax Polaris.

Answer 36

Evidently, my book wasn't good enough to help. I was reading through some of this, after p.4, that seemed that it might help some. http://mysite.science.uottawa.ca/vbozi013/mat1339/ch08.pdf
PaxPolaris' site is good too :)

Answer 37

Yay PaxPolaris for the help !

Answer 38

i think i missed the original problem as stated