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\[t(x)=60(\frac{1}{2})^{\frac{x}{30}}+20\]
initial temp is what you get when t = 0, namely 60 + 20 = 80
god it this slow!!
what merstj said
then set = 28 and solve for t
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or rather solve for x
\[T(x)=60(\frac{1}{2})^{\frac{x}{30}}+20\] \[60(\frac{1}{2})^{\frac{x}{30}}+20=28\] \[60(\frac{1}{2})^{\frac{x}{30}}=8\] \[(\frac{1}{2})^{\frac{x}{30}}=\frac{8}{30}=\frac{4}{15}\]
\[\frac{x}{30}=\frac{\ln(\frac{4}{15})}{\ln(\frac{1}{2})}\]
damn is this slow. i think i am done for the night
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