Question

Let R be the region bounded by the X- axis , the graph of y=Sqrt(X+1) and the line x=3.Find the area of the region R.

Answer 1

So you're just doing an integral? Calc II, right?

Answer 2

If you're doing an integral, you first need to know the lower and upper limits of integration. If you graph this, it's a sideways parabola with an x-intercept at x=-1. That's the lower limit. The upper limit is at x=3.

\[\int\limits_{-1}^{3}\sqrt{x+1}\]

Answer 3

thanks brine i got it from there

Answer 4

OS froze up on me. It's happening all the time.

Answer 5

hehe forgot the dx

Answer 6

hey can you help me with another problem though

Answer 7

it says let the function given by f(x)=4xe^3x i need to find the lim as x aproaches -infinty and limit as x aproaches infinity

Answer 8

Btw, for your integral, I got 16/3.

As for the limit, you can drop out the constants b/c they really don't matter for this problem. Same thing for when you're taking limits involving division of polynomials.

x*e^x

As x approaches -infinity, you get -x/e^x. Translation: (-large number)/(GINORMOUS EXPONENTIAL NUMBER)

Therefore, the ginormous exponential number wins out, and the function approaches zero as x approaches -infinity.

As x approaches positive infinity, the f(x) goes to positive infinity.