Let f:R-R be a function defined by f(x) $$f(x)=- \frac{|x|^3+|x|}{1+x^2} $$ then the graph lies in the
A.1st & 2nd Quadrant
B.1st & 3rd Quadrant
C.2nd and 3rd Quadrant
D.3rd & 4th Quadrant

Question

Let f:R->R be a function defined by f(x) $$f(x)=- \frac{|x|^3+|x|}{1+x^2} $$ then the graph lies in the 
A.1st & 2nd Quadrant
B.1st & 3rd Quadrant
C.2nd and 3rd Quadrant
D.3rd & 4th Quadrant

zarkon · Answer

looks like f is always negative...

zarkon · Answer

or zero

diyadiya · Answer

so 3rd and fourth?

zarkon · Answer

yes

anonymous · Answer

since both numerator and denominator are positive, and there is a big fat minus sign out front

diyadiya · Answer

What about 2nd and 3rd?

zarkon · Answer

the graph is never in the 2nd quadrant

zarkon · Answer

the domain for this function is all reals...but the y values are zero or negative..thus just the 3rd and 4th quads

zarkon · Answer

to make you notation nicer you can use 

$$f:\mathbb{R}\to\mathbb{R}$$
f:\mathbb{R}\to\mathbb{R}

:)

diyadiya · Answer

Ok Thank you :D