Question

integral problem?

Answer 1

\[\int\limits_{0}^{\ln2}e ^{2x}\]

Answer 2

what you want to do is:u-subsitution

Answer 3

du=2e^2x right?

Answer 4

[e^2x/2] -- ln2 - 0

Answer 5

i mean let u=2x

Answer 6

i got \[e ^{2\ln2}-e ^{0}\]

Answer 7

then du=2 dx, which means that dx=du/2

Answer 8

3/2

Answer 9

once you integrate that and remeber to replace the u with 2x, you can evaluate at the limits, no problem at all

Answer 10

i got
\[1/2\times(e ^{\ln2}-1)\]

Answer 11

thats 1/2 ... should be 3/2