Question

How many grams of zinc metal will react completely with 8.2 liters of 3.5 M HCl? Show all of the work needed to solve this problem.

Zn (s) + 2 HCl (aq) ZnCl2 (aq) + H2 (g)

Answer 1

Using the equation for molarity: M=moles/liters, we can plug in our given.

3.5M HCl = moles/8.2L

moles of HCl = 28.7

Now that we have our moles of HCl, we can use the mole to mole ratio in order to find moles of Zn.

28.7 mol HCl * (1 mol Zn/ 2 mol HCl) = 14.35 moles of Zn

Next, we just convert our moles of Zn to grams:

14.35 mol Zn * (65.39g Zn/ 1 mol Zn) = 938g Zn

Answer 2

Forgot about sig figs, the answer should be 9.4*10^2 g Zn