What is the mass defect (in amu) of a 60/27 Co nucleus whose nuclear mass is 59.9338 amu? What is the mass defect in kilograms? What is the energy equivalent of this mass in kilojoules?

Question

jfraser · Answer

If it's an atom of Co-60, then there are 27 protons and 33 neutrons. Find the expected mass of each of those pieces$$27 p^{+1} * 1.007825 amu$$ + $$33n^{0} * 1.008665 amu$$
should be
$$60.49722amu$$ since the actual mass is 59.9338amu, what's the defect?

anonymous · Answer

60/27 Co

jfraser · Answer

the defect is the difference between the mass of the nucleons (the protons and neutrons) and the mass of the atom as a whole. The mass of particles should be 60.49722amu, but the actual mass is only 59.9338amu. What's the mass defect?

anonymous · Answer

is it 7

jfraser · Answer

what is the difference between 60.49722amu and 59.9338amu?

anonymous · Answer

about 1

jfraser · Answer

0.56342amu, which is the mass defect

anonymous · Answer

so What is the energy equivalent of this mass in kilojoules?

jfraser · Answer

turn that mass in amu into kilograms, then use mc^2, where c is the speed of light, to find the energy change in joules

anonymous · Answer

so its 1.12684k