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Mathematics 16 Online
OpenStudy (anonymous):

PLEASE HELP ME FOR MEDALS!!! a.) On graph paper, graph ΔABC if A(3, 0), B(2, 7), and C(6, 4). What is the best name for this triangle? Justify your answer using slope and/or lengths of sides. b.) On graph paper, graph ΔABC if A(3, 0), B(2, 7), and C(6, 4). Find mA. Explain how you found your answer

OpenStudy (shayaan_mustafa):

@ari<3 We are not for medals here. We are volunteerily help needy ones. Like you. Never give us lust for medals. Thank you.

OpenStudy (anonymous):

i'm sorry...i didn't know. can you please help me?

OpenStudy (shayaan_mustafa):

becareful next time. well have you draw diagram?

OpenStudy (anonymous):

no.

OpenStudy (accessdenied):

get some graphing paper and try graphing the points first. :) we can think about the question with a picture

OpenStudy (anonymous):

okay

OpenStudy (shayaan_mustafa):

@AccesDenied he is right.

OpenStudy (anonymous):

|dw:1332971804201:dw| it looks like this when i drew it on the graph,.. is then an isocless?

OpenStudy (accessdenied):

I get this (attachment)

OpenStudy (anonymous):

oh yea i did it wrong sorry

OpenStudy (anonymous):

so equalaterial?

OpenStudy (accessdenied):

Well, we can figure it out by using distance formula between each side. We can have an equilateral (all sides =), a scalene (no sides =), or an isosceles triangle (2 sides =), so we can check those side lengths (AB, BC, and AC) to figure it out.

OpenStudy (anonymous):

isosceles

OpenStudy (accessdenied):

do you have the distances of sides already? or are you guessing based on what it looks like? :P

OpenStudy (anonymous):

what it looks like

OpenStudy (accessdenied):

okay... well, to 'prove' that it is isosceles, we have to give exact side lengths and show that they're equal. I don't think you could tell with those guesses for sure. Teachers would prefer the proof. :) We'll use this formula: \[ D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2};~~ for~(x_1,y_1)~ and~ (x_2,y_2) \]

OpenStudy (anonymous):

ok

OpenStudy (accessdenied):

As an example, here's the length of AB: \[ \begin{split} AB &= \sqrt{(\color{red}{3} - \color{blue}{2})^2 + (\color{red}{0} - \color{blue}{7})^2}~~~A(\color{red}{3,0}),~B(\color{blue}{2,7}).\\ &= \sqrt{(1)^2 + (-7)^2}\\ &= \sqrt{1 + 49}\\ &= \sqrt{50}\\ &= 5\sqrt{2}\\ \end{split} \]

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