a game is played in which a coin is tossed untill the third tail when the game stops, what is the probability that there will be at least three heads before the game stops...?
Each time you toss the coin you have a 1/2 probability it will be heads or tails. The probability of getting two of the same in a row is (1/2)(1/2)=(1/4) So it depends on how many iterations of throwing the coin were done.
that's the only information given...
It's tempting to say that the answer is 50% by symmetry, but I don't think that's actually true.
If the game stops in 6 or more flips, we know that there are 3 tails, so the rest must be heads, which means there are at least 3 heads. If the game stops in 5 or fewer slips, there can be at most 2 heads. The game can't stop in fewer than 3 flips. So, you only have to consider the cases of 3, 4, and 5 flips.
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