Question

Use the quadratic formula to find the roots of the equation. Round to tenths if necessary. x2 - 6x + 2 = 0
A. {0.4, 5.6}
B. {0.5, 4.8}
C. {1.4, 2.4}
D. no real number solution

Answer 1

x^(2)-6x+2=0

Use the quadratic formula to find the solutions. In this case, the values are a=1, b=-6, and c=2.
x=(-b+-sqrt(b^(2)-4ac))/(2a) where ax^(2)+bx+c=0

Substitute in the values of a=1, b=-6, and c=2.
x=(-(-6)+-sqrt((-6)^(2)-4(1)(2)))/(2(1))

Multiply -1 by each term inside the parentheses.
x=(6+-sqrt((-6)^(2)-4(1)(2)))/(2(1))

Simplify the section inside the radical.
x=(6+-2sqrt(7))/(2(1))

Simplify the denominator of the quadratic formula.
x=(6+-2sqrt(7))/(2)
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Simplify the expression to solve for the + portion of the +-.
x=3+sqrt(7)
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Simplify the expression to solve for the - portion of the+-.
x=3-sqrt(7)
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The final answer is the combination of both solutions.
x=3+sqrt(7),3-sqrt(7)

x=5.6458,0.3542

Answer 2

so D. ?

Answer 3

A

Answer 4

@AlexisDelgado