Question

Solve 3(7^x+1) = 10 -2(7^x+1)
I cant figure out what to do after the first step

Answer 1

Is it 3(7^(x+1)) or 3(7^(x)+1?

Answer 2

In other words, is the +1 in the exponent?

Answer 3

x+1 is the exponent, 7 is not

Answer 4

\[3(7^x+1) = 10 -2(7^x+1) \]
add 2(7^x+1) to both sides
\[5(7^x+1)=10\]
divide both sides by 5
\[7^x+1=2\]
-1 to both sides
\[7^x=1\]
\[\large \log_7(7^x)=\log_7 (1)\]
\[\large \cancel{\log_7}(\cancel{7}^x)=\log_7 (1)\]
\[x=\log_7(1)\]
\[x=0\]

Answer 5

oh blah didnt read the bit about the exponent until now

Answer 6

:( sorry sometimes it is difficult to write the problem as is

Answer 7

\[3(7^{x+1})=10-2(7^{x+1})\]
\[5(7^{x+1})=10\]
\[7^{x+1}=2\]
\[\log_7 7^{x+1}=\log_7 2\]
\[x+1=\log_7 2\]
\[x=\log_7 (2)-1\]

Answer 8

Thank you!! this is very helpful