Question

Water is pumped out of a holding tank at a rate of 5-5e^-0.09t liters/minute, where t is in minutes since the pump is started. If the holding tank contains 1000 liters of water when the pump is started, how much water does it hold one hour later?

Round your answer to one decimal place.

Amount of water in tank after one hour ? liters.

Answer 1

can u help me please

Answer 2

What is E?

Answer 3

its something that can be put on a calculator. Idk.

Answer 4

its on a calculator

Answer 5

I don't think I can help much.
My opinion is to substitute 60 for t, then divide 1000 by that. But that's obviously incorrect.

Answer 6

hello coco are u gonna anser?

Answer 7

hello

Answer 8

Give him/her some time.

Answer 9

They have a long answer for you. Patience may help.

Answer 10

k

Answer 11

I have got the method already and I am now solving the equation

Answer 12

thank u

Answer 13

volume of the water pumped out =integral 5-5e^-0.09t = 5t - 5(-1/0.09) e^(-0.09t)
after 1 hour which is 60min , volume pumped out= 5(60)-5(-1/0.09)e^((-0.09)(60)) = 300.3
volume remained = 1000-300.3= 699.7

Answer 14

sorry that it spends you quite a long time to wait. I thought in wrong way at the beginning but now it should be correct.

Answer 15

is 699.7 the answer. I ahve to get it right

Answer 16

Chlorophyll help meee someone!

Answer 17

OMG can one of u just say something please.

Answer 18

lol is anyone uh there? I have four problems left on this quiz that i hae been doing for like almost four hours and its only ten questions! im now irritated

Answer 19

I hate u, the answer was wrong. FML

Answer 20

wrong?

Answer 21

= 5∫ ( 1 - e ^ (-.09t ) dt [ 0, 60 ]
= 5 ( t + e ^ (-.09t ) / .09 ) [ 0, 60 ]
= 244.7 L
Volume remain after 1 hr: 1,000 - 244.7 = 755.3

Answer 22

Hey, we do the best, but not guarantee it's 100% correct. It's your resposibility to double check.