Find the next three terms of the sequence. Then write a rule for the sequence. 648, 216, 72, 24
8,4,2..... or 8,8/3,8/9.....
if u tell me which one is rite i shall tell u the rule.......
Rohan think and reply.....
8,4,2..... or 8,8/3,8/9.... it will be going on on and onnnnnnnn
u dont be a barrier
the rule plzzzzzz!
which one is rite 8,4,2 or 8,8/3,8/9
the second
the first
@Rohangrr ure wrong once again so thats why i said think and reply!
is the answer the 2nd
@daja2fly the rule is that see, 648 can be written as 2^3*3^4 216 can be written as 2^3*3^3 72 can be written as 2^3*3^2 24 can be written as 2^3*3^1 the next term will be 2^3*3^last power -1 then 2^3*3^0 then 2^3*3^-1 then 2^3*3^-2... and so on....!!!!!
understood?
i get the sequence but not the actual rule how would i write that
u can write it as 2^3*3^last power-1 \[2^{3} \times 3^{x _{l}-1}\]
where \[x _{l}\] is the previous power
ok?
This is a geometric series where the first term is 648 and the common ratio is 1/3. The next term would be 24(1/3) or 8, and the next is 8/3 etc. The expression for the nth term would be:\[a _{n}=(648)(1/3)^{n-1}\]. Substituting and solving for the fifth term:\[a _{5}=648(1/3)^{4}=648(1/81)=8\]
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