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Chemistry 7 Online
OpenStudy (anonymous):

what things can we conclude by seeing electronic config of an element.Please explain in terms of grp no, period, etc

OpenStudy (anonymous):

the highest value of principal quantum number gives the period number

OpenStudy (anonymous):

hmm and??

OpenStudy (anonymous):

half filled or full filled,and correspondingly its stability.

OpenStudy (anonymous):

How many elements should be there in total if all th 7s 7p 6d and 5f block are to be full

OpenStudy (anonymous):

help me here please ^^^

OpenStudy (anonymous):

doesnt 7s fulfilled mean that 1s,2s,3s,4s...6s fulfilled..how can 7s be filled wothout these getting filled earlier

OpenStudy (anonymous):

ok ok I thought that it was saying to calculate elements in nly these 7s, 7p ...

OpenStudy (anonymous):

i think the question meant how many elements would you find in the periodic table if elements were discovered upto that which has filled 5f shell

OpenStudy (anonymous):

so 7*2 means - 2 for 1s, 2 for 2s, 2 for 3s, 2 for 4s, 2 for 5s, 2 for 6s, 2 for 7s =14 14 for 4f , 14 for 5f = 28 10 for 3d, 4d, 5d, 6d = 40 6 for 2p, 3p, 4p, 5p, 6p, 7p= 36 TOTAL = 118 elemets I GUESS IS THE CORECT ANSWER

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

M I RIGHT??

OpenStudy (anonymous):

totally....i think i should relearn multiplication..silly mistakes i make.but yes, i think you are correct.my final answer came same as you

OpenStudy (anonymous):

NO NO u was mistaken in taking 5 * 14 while there are no f orbital for 1, 2, 3 so it was 2*14 and u took 7*6 but 1 dont have p orb so it was 6* 6 also 6*d should have taken as 4*6 bcz thr are no d orbital for 1,2,

OpenStudy (anonymous):

*were

OpenStudy (anonymous):

although Im not sure abt my answer...I would lke anyone to verify my answer

OpenStudy (anonymous):

instead of writing 5f, i wrote 5*14. and to do shortcut,u make some mistakes

OpenStudy (anonymous):

i didnot make the mistake of couting d... i know which n corresponds to which l....although it may look different, i know it was computation mistake...i had it right in my mind........so i realize that jaldi karne se galti hota hai

OpenStudy (anonymous):

ok ok r u sure ki this answer is right??

OpenStudy (anonymous):

checked again and again this time..dont feel so...feel pretty confidant...which class are u in...ur question gave me an opportunity for revising atomic structure. thanks

OpenStudy (anonymous):

which city?

OpenStudy (anonymous):

new del

OpenStudy (anonymous):

my 11 board exams going on and am from kolkata. if u have more questions,do ask.

OpenStudy (anonymous):

yes i will... i will for sure ... i am dumb in my studies...specially in chem

OpenStudy (anonymous):

doesnt matter. do differently in 12. u sound to do goog

OpenStudy (anonymous):

ok tell me n, l,m for 3px orbital my answer is n=3 , l= 0,1,2 and m= 1, 2, -1, -2 m I right???

OpenStudy (anonymous):

for m , its -l to +l , that includes 0 . so -2,-1-0,1,2. remember that number of values of m is equal to 2l +1

OpenStudy (anonymous):

obvoiusly -0 =0

OpenStudy (anonymous):

also magnetic spin quanum no= +1/2 , -1/2 and what u said above that m= 0,1,2 ,-1,-2 OK? ha ha -0 =0

OpenStudy (anonymous):

it may sound simple,but one day i was asked to prove -0 = 0 . even that + - we use has a lot of mathematically hifis attached

OpenStudy (anonymous):

m= 2l +1 . so there should be 5 values of m , putting l =2 and m ranges from -l to +l

OpenStudy (anonymous):

ok next one is- here 0.280g of Fe is treated with excess of (BaOH)2. Cal the weight of precipitate. eqn is Fe2 (SO4)3 + 3Ba(OH)2 ---> 2Fe (OH)3 + 3BaSO4 (at mas Fe-56, Ba-137, O-16 H-1 S-32)

OpenStudy (anonymous):

would u prefer i do by unitary method,or ratio method, or poac theory or number of equivalence

OpenStudy (anonymous):

my answr is 1.165 gm please chk , and do wth any method i just need to chk answers

OpenStudy (anonymous):

0.28 gram ferrous sulphate or fe?

OpenStudy (anonymous):

Ferric ions sorry

OpenStudy (anonymous):

0.28 gram of ferric sulphate then?

OpenStudy (anonymous):

this is the point to think---> 0.280 of Ferric ions is reacted .and we have to find BaSO4 (which is precipitate)

OpenStudy (anonymous):

mine is coming 0.1498. dont your book have ans at the back

OpenStudy (anonymous):

no please share steps

OpenStudy (anonymous):

number of equivalence for any reaction is constant. number of equivalence = weight of sample divided by equivalent weight. do it in your calculator. valency factor ferric sulfate is 6 and that for ferric hydroxide is 3

OpenStudy (anonymous):

ok i will do later i think i need to re think. now next Determine the molecular formula of a compund which contains 2.19% H, 12.8% C , 85% Br . 1g of compund occupies 119 ml of volume at stp .

OpenStudy (anonymous):

take ratio of percentages and atomic weight. then take them to their simple whole number forms. ths gives ratios of atomicities of compoung..i.e emperical formula...

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