You and a friend play a game in which you each toss a coin. You score a point for each head and your friend scores a point for each tail. The first person to score ten points wins. The score is 8 to 6 in your favor. Describe a simulation that completes the game and use it to find an experimental probability that your friend will win.
Hmmm, are decision trees valid as an answer?
So in 2 plays there's a 1/4 (.25) chance that you've won, whereas there's a 3/4 (.75) chance that you haven't. In 3 plays your chances of having won are .375, and having not won is the remainder .625. So, I guess you could say that after two plays your chances of having won increase at .5/n where n is the number of plays the 'y-intercept' is .25...? Sure there's someone with a better idea about where this is going...probability was never my favourite subject, might have another look tomorrow.
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