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Mathematics 8 Online
sam (.sam.):

Is it just me or the wolfram sometimes wrong

sam (.sam.):

Try to differentiate \[y=\frac{\sqrt{4t-1}}{3t-5}\] and compare the answer with wolfram

OpenStudy (turingtest):

not just you

OpenStudy (anonymous):

i have seen it give rather bizarre and lengthy "show steps" for relatively simple integrals i don't know if that counts as "wrong"

OpenStudy (turingtest):

but sometimes it's hard to tell; they factor things in a crazy way sometimes

OpenStudy (turingtest):

I have found wolf to be flat out wrong on multiple occasions, especially with DE's

sam (.sam.):

The sign '+' or '-' switches in the denominator sometimes

OpenStudy (anonymous):

this looks good though http://www.wolframalpha.com/input/?i=sqrt%284x-1%29%2F%283x-5%29

sam (.sam.):

This is what ive got for the equation on top \[\frac{dy}{dt}=\frac{(3t-5)\frac{1}{2\sqrt{4t-1}}(4)-\sqrt{4t-1}(3)}{(3t-5)^{2}}\] \[\frac{dy}{dt}=\frac{2(t-5)-3(4t-1)}{(3t-5)^{2}(4t-1)^{1/2}}\] \[\frac{dy}{dt}=\frac{-10t-7}{(3t-5)^{2}(4t-1)^{1/2}}\]

OpenStudy (anonymous):

it is fond of writing polynomials from the bottom up though. a fairly natural thing to do if you think of power series

sam (.sam.):

wolf's answer \[\frac{-6 t-7}{(5-3 t)^2 \sqrt{4 t-1}}\]

OpenStudy (anonymous):

i think you forgot the 2 up top

OpenStudy (turingtest):

I nener use the quotient rule, product rule is always easier

OpenStudy (turingtest):

never*

sam (.sam.):

the 2?

OpenStudy (anonymous):

\[\frac{dy}{dt}=\frac{(3t-5)\frac{1}{2\sqrt{4t-1}}(4)-\sqrt{4t-1}(3)}{(3t-5)^{2}}\times \frac{2\sqrt{4t-1}}{2\sqrt{4t-1}}\]

sam (.sam.):

the 4 divide the 2

OpenStudy (anonymous):

i think, i didn't do it with pencil and paper

OpenStudy (experimentx):

looks like you forgot to multiply by 2

OpenStudy (anonymous):

oh maybe a typo here \[\frac{dy}{dt}=\frac{2(t-5)-3(4t-1)}{(3t-5)^{2}(4t-1)^{1/2}}\]

sam (.sam.):

\[\frac{dy}{dt}=\frac{(3t-5)\frac{1}{\sqrt{4t-1}}(2)-\sqrt{4t-1}(3)}{(3t-5)^{2}}X\frac{\sqrt{4t-1}}{\sqrt{4t-1}}\]

OpenStudy (anonymous):

i think you just dropped the 3 in front of the t in the first term

OpenStudy (anonymous):

so i was wrong about the 2, but rather the error is \[\frac{dy}{dt}=\frac{2(t-5)-3(4t-1)}{(3t-5)^{2}(4t-1)^{1/2}}\] should be \[\frac{dy}{dt}=\frac{2(3t-5)-3(4t-1)}{(3t-5)^{2}(4t-1)^{1/2}}\]

OpenStudy (experimentx):

2(3t-5) -(4t-1)3 = -6t-7 wolfram is right

sam (.sam.):

Oh that's a noob move, forgot the 3, LOL

OpenStudy (anonymous):

oh well, one for technology...

sam (.sam.):

but still, the sign (3t-5) at the bottom for wolf is switched

OpenStudy (anonymous):

it is squared

sam (.sam.):

Yeah it doesnt matter

OpenStudy (anonymous):

wolf likes \[a_0+a_1x+a_x^2+...\] rather than the other way around

sam (.sam.):

hmm never thought of that

sam (.sam.):

Medals for all! :D

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