Question

16ax + 4x2 +16a2 factor please?

Answer 1

16ax+4x2+16a2 = 4(x2+4ax+4a2)
=4(x+2a)^2

Answer 2

Gahhh i still don't understand.. is there like an easy way of explaining this to me??

Answer 3

4x^2+16ax+16a^2=
4(x^2+4ax+4a^2)
we want to factor what's in the parentheses
ax^2+bx+c
a*c=4
we need 2 factors of 4 than add to 4, those factors are 2 & 2
4(x^2+2ax+2ax+4a^2)=
4[x(x+2a)+2a(x+2a)]=
4[(x+2a)(x+2a)]=
4(x+2a)^2

Answer 4

look up "factor by grouping" or the "ac method"

Answer 5

Haha i was just reading the ac method.. Thanks! :) I'll see if i figured it out... and i'll message you if i need more help! :)

Answer 6

you lost me right here
we want to factor what's in the parentheses
ax^2+bx+c
a*c=4

Answer 7

i just wrote ax^2+bx+c because thats the standard form of a quadratic

Answer 8

you can have anything for a, b, or c, but its letting you know that a is the coefficient of x^2, b is the coefficient of x, and c is the constant

Answer 9

alright thanks :)