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The numbers in the row of Pascal's triangle corresponding to 5 tosses of a coin must sum to 32.
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so again, what's the question....???
how do I explain whether it is false or true?
All you have to say is that "it follows from the definition of Pascal's triangle that its fifth row sums up to 32." :P
for n trials, the sum of the terms is \[2^{n}\]
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thanks everyone!
it could be easily proven....the different terms in the pascals triangle for 'n' trials are the coefficients of x^0,x^1 and so on in the expansion of \[(1+x)^{n}\] and to eliminate all terms of x and get the coefficients(as sum) just put x=1... which obviously mean \[2^{n}\]
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