Please help me to understand.

y ^(-1/5)
I changed problem to 1/y^(1/5) after this point I am not sure how to solve once its in radical form

Question

Please help me to understand.

y ^(-1/5)
I changed problem to 1/y^(1/5) after this point I am not sure how to solve once its in radical form

amistre64 · Answer

its an expression, not an equation

amistre64 · Answer

what constitutes a solution to a statement?

savvy · Answer

you cannot solve it any further until and unless it is equal to something...

anonymous · Answer

guessing y^(1/5)=$$\sqrt[5]{y}$$

yrivers36 · Answer

Ok so I did have it right.  Thank you so much

anonymous · Answer

I just changed the form of the equation. hint is look at the fraction and that what the sqrt will be powered to

yrivers36 · Answer

ok so then it will be the denominator and one the numerator

anonymous · Answer

for the most part yes.

yrivers36 · Answer

Thank you for your help

anonymous · Answer

y^(1/2)= is just $$\sqrt{y}$$ because the sqrt is equal to second power that's why if you ever want to get rid of the sqrt just sq it

yrivers36 · Answer

it was y^(-1/5)

anonymous · Answer

i know. i was just giving an example

yrivers36 · Answer

oh ok sorry

anonymous · Answer

no worries have a good one

yrivers36 · Answer

you too