Question

Find the center & radius for the following:
1. 2x^2+2y^2=72
2. (x-3)^2+(y-1)^2=4
3. (x-5)^2+(y+2)^2=49
4. (y-4)^2+(x-10)^2=64

Answer 1

these are all circles
the circle equation is:
(x-h)^2 +(y-k)^2 = r^2

center: (h,k)
radius is r

Answer 2

1)Center is (0,0) radius=6
2)Center is (3,1) radius=2
3)Center is (5,-2) radius=7
4)Center is (10,4) radius=8

Answer 3

Your amazing! i have a few more.

Answer 4

1. (x^2-6x+9)+(y^2+8y+16)=1

Answer 5

Center is (3,-4) radius=1

Answer 6

2. x^2+12x+y^2-8y=-27

Answer 7

Center is (-6,4) radius=5

Answer 8

Write an equation for the circle with center at (3,-4) and with (2,-1) a point on the circle.

Answer 9

omg, amazinggggg. (:

Answer 10

\[x^2+y^2-6x+8y+15=0\]

Answer 11

My multiple choice answers are:
(x-2)^2+(y+1)^2=1
(x+2)^2+(y-1)^2=10
(x-3)^2+(y+4)^2=10
(x-3)^2+(y+4)^2=5
(x+3)^2+(y-4)^2=100

Answer 12

C

Answer 13

Your so smart.

Answer 14

Glad to help