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find the area between the following curves: 3 square root x and y=x
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first you need to set them equal. presumably you mean \[y=\sqrt[3]{x}\] and \[y=x\]
yes
|dw:1333070327513:dw|
then the limits of integration will be where they meet, namely at x = 0 and x = 1
in that interval \[\sqrt[3]{x}>x\] so you integrate \[\int_0^1\sqrt[3]{x}-xdx\]
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i never bother with top and bottom; i just take the absolute value of the results
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