According to the Consumer Electronics Manufacturers Association, 10% of all U.S. households have a fax machine and 52% have a personal computer. Suppose 91% of all U.S. households having a fax machine have a personal computer. A U.S. household is randomly selected. a) a. What is the probability that the household has a fax machine and a personal computer? b) What is the probability that the household has a fax machine or a personal computer?
According to the Consumer Electronics Manufacturers Association, 10% of all U.S. households have a fax machine and 52% have a personal computer. Suppose 91% of all U.S. households having a fax machine have a personal computer. A U.S. household is randomly selected. a. What is the probability that the household has a fax machine and a personal computer? p = b. What is the probability that the household has a fax machine or a personal computer? p = c.What is the probability that the household has a fax machine and does not have a personal computer? p = d. What is the probability that the household has neither a fax machine nor a personal computer? p = e. What is the probability that the household does not have a fax machine and does have a personal computer? p = Round the answers to 3 decimal places. The tolerance is +/- 0.005 I don't want to do your entire homework for you, but this should make it easy: Pfax=0.1, Pnofax=0.9 Pcomp=0.52, Pnocomp=0.48 Pcomp|fax=0.91,Pnocomp|fax=.09 Now the strategy to solve this: First devide between fax and nofax then in the cases fax=0 devide with Pcomp|nofax and Pnocomp|nofax, otherwise devide with Pcomp|fax and Pnocomp|fax Given Pfax and Pcomp|fax and Pcomp you can calculate Pcomp|nofax
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