Question

Product (3a+4) (2a-1)

Answer 1

3a/4 + 1 = (2a - 1)/3
for now, work on the right side: divide through by 3 to make it "(2a/3) - (1/3)"
this brings your equation to: 3a/4 + 1 = 2a/3 - 1/3
now you can isolate all the terms that include an a to one side, by subtracting the 2a/3 from both sides (remember what you do to one side, you must do to the other)
3a/4 - 2a/3 + 1 = 2a/3 - 2a/3 - 1/3
and that equals;
3a/4 - 2a/3 + 1 = -1/3
then subtract the 1 from both sides, in order to move it to the right side:
3a/4 - 2a/3 +1 -1 = -1/3 - 1,
which equals:
3a/4 - 2a/3 = - 4/3
now use a common denominator of 12 on the left side and subtract:
3*3a/12 - 4*2a/12 = -4/3
which equals:
9a/12 - 8a/12 = - 4/3
now subtract the fractions:
1a/12 = -4/3
then multiply both sides by 12:
a = 12 * (-4/3) = -16
now check the answer by plugging it back in:
3*(-16)/4 + 1 = (2*(-16) - 1)/3
gives:
-11 = -11

Answer 2

(3a+4) (2a-1) = 6a^2 -3a +8a -4=6a^2 +5a -4

Answer 3

so finally (3a+4) (2a-1) = 6a^2 -3a +8a -4=6a^2 +5a -4