Question

I've shown my friends this one... but now I'm confused, I'm not sure if my version of solving this is right, I'd like to know what's your version...

http://i1064.photobucket.com/albums/u368/Kreshnik-joker/27.jpg

Thank you

Answer 1

anyone??

Answer 2

The problem is is that the second version becomes 27... because (-3^2)=9
9 ^2/3 = 27

whereas (-3)^3 = -27 because i'ts -3 times -3 times -3

Answer 3

It is not \[\LARGE (-3^2)=9\] is \[\LARGE (-3)^2=9\] there's nothing wrong, I think the problem is somewhere else.... can I show my version??

Answer 4

Ok. Show :)

Answer 5

I think...\[\LARGE (-3)^{3}=\left[(-3)^{2}\right]^{\frac32}=(-3)^{\frac{3}{2}}\cdot (-3)^{\frac32}\]

and this becomes....

\[\LARGE (\sqrt{-3})^3\cdot (\sqrt{-3})^3 =i\cdot \sqrt3 \cdot i\sqrt3=i^2\cdot 3=-1\cdot 3\]

I forgot the exponents 3/2 but you have the idea... could this be correct ?? :O

Answer 6

exponents 3 cubes not 3/2

Answer 7

Kreshnik, I really have no idea if this is correct... You could ask someone else... but even if this were correct, why not stick with the simple -27 answer? lol

Answer 8

haahhaahha.... LOL , you're right, but I was wondering where the minus went ! ... anyway... thanks for the help, I'll go and get dizzy my professor, let's see if he know it LOL ahhaahah... :P thank again. ;)

Answer 9

Glad I could even give a little help! haha.

Answer 10

:D