$$\int \frac{1-2cos x}{sin^2x}dx=$$

How to get out of the fraction?

Question

$$\int \frac{1-2cos x}{sin^2x}dx=$$

How to get out of the fraction?

amistre64 · Answer

i might consider multiplying by 2/2

amistre64 · Answer

or is that a different identity that im thinking of

anonymous · Answer

divide each term by 
$$\sin^2(x)$$ would do it

amistre64 · Answer

1/sin^2 = csc^2 which ints up by basic trig stuff

-2cos/sin^2 tho ... is 2 cot(x)csc(x)

amistre64 · Answer

yes, it would do it :)

anonymous · Answer

good morning
lots of new features i see
left side looks like a three ring circus

amistre64 · Answer

yeah, its a bit of a distraction to me

amistre64 · Answer

also, to police or find questions now i have to flip back and forth between open and closed

eyust707 · Answer

yes but now people dont post a million ?s at once

anonymous · Answer

$$\int\frac{1}{\sin^2(x)}dx-2\int \frac{\cos(x)}{\sin^2(x)}dx$$

amistre64 · Answer

they still post them, they just have them all lined up in the closed list

anonymous · Answer

it would be nice if there was an explanation of the new features, it is hard to teach an old dog new tricks

amistre64 · Answer

:)  theres a new release posted in the feedback section

eyust707 · Answer

=P

anonymous · Answer

$$\int\frac{1}{\sin^2(x)}dx=\int csc^2(x)dx=-\cot(x) $$second one is a u-sub

anonymous · Answer