Question

find f'(x): f(x) = x*sqrt(2-x^2)

Answer 1

looks like a product and a chain wrapped together with some other basics thrown in for good measure

Answer 2

f(x) = x*sqrt(2-x^2)

f'(x) = (x*sqrt(2-x^2))'

f'(x) = x'sqrt(2-x^2) + x*sqrt(2-x^2)'

f'(x) = x'sqrt(2-x^2) + x*sqrt(2-x^2)' * (2-x^2)'

Answer 3

\[x \sqrt{2-x ^{2}} - (x ^{2}/\sqrt{2-x ^{2}})\]

Answer 4

(2-2x^2)/sqrt(2-x^2) thanks i got it tho