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The SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission process in the Cesium atom. Calculate the wavelength of this radiation (to 3 sig figs). In which region of the electromagnetic spectrum is the wavelength found?
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So we know that frequency is equal to the speed of light over lambda which is wavelenght from this equation:\[f={c \over \lambda}\] We just switch frequency with wavelength and get\[\lambda = {299,792,458 m(s) \over (s) (9,192,631,770cycles)}\] The seconds cancel and you get meters per cycle which is wavelength. Convert to nano meters and you get an answer with a power to the 7th which is microwaves.
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