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\[-\sqrt[4]{81}\]
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Well, what's the square root of 81?
\[-\sqrt[4]{81}\]
9
Right, and \[ \sqrt[4]{81} = 81^{1/4} = (81^{1/2})^{1/2} = 9^{1/2} = .... \]
why dis 1/4 break down into 1/2?
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because \[ x^{ab} = (x^a)^b \] and \[ \frac{1}{4} = \frac{1}{2} . \frac{1}{2} \]
Hence \[ x^{1/4} = x^{(1/2)(1/2)} = (x^{1/2})^{1/2} \]
& wouldn't it go to>>> \[\sqrt[2]{9}\] = 3
Yes. And that makes complete sense because \( 3^2 = 9 \) and hence \( 3^3 = 27 \) and hence \( 3^4 = 81 \).
\[-\sqrt[4]{81}=-\left(\sqrt[4]{81}\right)=-3 \]
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so is the answer -3 or 3 ? & why?
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