Question

Pretty easy. but i want steps.
Thanks in adv.

Q2.
http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_s03_qp_1.pdf

Answer 1

the link is broken :)

Answer 2

http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_s03_qp_1.pdf

Answer 3

It isn't here. Is this the question you want?
Find all the values of x in the interval 0◦ ≤ x ≤ 180◦ which satisfy the equation sin 3x + 2cos3x = 0.

Answer 4

Yes.

Answer 5

too difficult for me, maybe in a few years :)

Answer 6

months*

Answer 7

Yes @MelindaR

Answer 8

lol*

Answer 9

I don't remember how to do it, let me revise some material

Answer 10

can u please try Q10 (iii)

Answer 11

Find where it crosses the y-axis, and integrate with upper limit there and lower limit x=1

Answer 12

the upper limit as ?

Answer 13

sorry i meant x-axis

Answer 14

the upper limit as the point where it crosses the x-axis, if there is multiple use the one which is greater than 1 since you have to integrate in that region

Answer 15

or if its between 1 and 0 then use it as the lower limit and use x=1 as the upper limit

Answer 16

but im confused between, x-axis, the y-axis and the line x = 1. as the question says

Answer 17

so use x=1 as the upper limit and then the lower limit depends on whether it crosses the x-axis between 0 and 1, if not then you can just use the lower limit x=0, otherwise you have to find x where it crosses the x-axis and use that as the lower limit

Answer 18

what about the y-axis then?

Answer 19

the y-axis is at x=0

Answer 20

and that is why the minimum lower limit you should take should be x=0, but

Answer 21

because you don't want regions below the x-axis too, you have to find where the graph crosses the x-axis and include those limits in your integral

Answer 22

so upper = 1 and lower = 0 ?

Answer 23

yeah, but if it crosses the x-axis between 0 and 1 then you will have to take that into account